Hamming Code - error detection and correction

bro you are oooooooooooooooosm.......................thanks....

thanks for helping me to understnd haming code .Its nice explaination .Easy to understand

You explained in 5 minutes what my professor couldn't explain in 4 hours. Thank you sir.

thank you for such magical explanation <3

can an error occur on a parity bit?

this is really great
can you do a tutorial for BCH codes and RS codes
?

Finally someone who got it right. Thank you for your very clear and brief explanation for what is so easy in the end.

what to be do if all parity checking is even at last??

cool dude...great ..

thank you so much...very well explanation

thanks Mr. Hamilton...!

great explanation. Thanks

you've made an error in p2 😑

you saved my exam love you sir ..... no homo 😂👌👌👌👌😘

Thanks for the video you're awesome...it really helped...I was so confused about it!

excellent explanation

thank u so much!

thank u so much. last minute life saver!

My gosh that might be the coolest thing I've ever seen, these computer science chaps are smart guys, hey?

why are you using the parity bits that are transmitted to calculate how the parity bits should look if the word was right?

thank you so much Sir for the video !!!

thankyou 🙃

Why does the parity p2 and p8 is N(does not match) after the error?

Thanksss, 1 hour left to study for the mid exam :)

Thanks allot !

Super useful. Thank you for this. Every other explanation I've found on this seemed needlessly confusing.

Thanks Wayne

You just got me smiling. It couldn't be explained any better.

can u get me the answer for - 110101100011001?

Thanks alot Wayne for ur time.So this means you took even parity by default.But just out of curiosity coz i watched other videos also,it was solved in another way i.e dey kept parity as a variable nd solved accordin to even parity.Both should go i guess.I ll try and report back :)

I have a query-
p1- p1 0 1 0 1 1 - odd ones
p2- p2 0 0 0 1 1 -even
p4- p4 1 0 0 1 - even
p8- p8 1 1 1 1 -even
If i dont write the parity value (like u did),i dont get the correct answer.Also if m not wrong didn't mention the condition whether you are checking even/odd parity.
Thanks

Wow, the past 2 videos perfectly explained this concept to me... thank you so much!

Absolutely stunning and crystal clear explanation. Thank you for your work!

thank you very much!

I think this is wrong. When you check the parity bits you usualy don't count them in also for checking. For instance: when you checked if P1 is ok you also put value '0' there. Why would you consider the value of P1 ? Isnt that the value that you are checking ?

wow...that was surprisingly easy, a lot easier than my teachers explanation nd strange venn diagrams which im not sure how to understand . Thanks!!!

Thanks for the video

Simple and informative. Thank you very much!

I loved this video.  Thank you!

Magic of Hamming's code, now I am curious as to how Hamming did it,pure genius.

Really nice video.

Fantastic, thank you! :)

It helps me to understand the method properly... Thank you.

I understand this more than i ever would using the AQA AS computing book. Thanks for uploading this. My exam is tomorrow so this helps a lot.

Couldn't been any better. Brilliant explanation!! Thank you sir :D

really nice explanation..
and he certainly sounds like Bennedict Cumberbach..!!..!!..!!

what if in the end i got P2, P4 and P8 as the N.
so that means 2 + 4 + 8 = 14 right? so the error is in the 14th bit, wait what??
can you explain it to me, sir? thanks

im sorry im really confuse about P2 and P8. they have odd bit. and the value is 1 right. and i believe from what i get from you is the value of p2 and p8 are the same with the parity before , so it must be matched with the parity before. i dont know im just confuse. would be glad if you can clarify me. Thanks sir

should win the Nobel teaching prize