Discrete Time Convolution (Tabular Method)

Y[n]={2,-3,4,-2,1} (2<--) answer of the homework questions

y(n)= (2,-3,4,-2,1). 4 is the valu of zero.

Thank you sir that was very helpful ❤

Thank you very much sir.....
Please I want to ask if y(n)={-2,-1,0,3,2,1,8} and x(n)={4,-1,1,2} find the system response h(n)
How would I go about it...... thank you

this isnt te tabular method. this is the matrix method

This video Save my life

Thanks

is it tabular or matrix

If n=0 is not given or represented in given problem then how to find it

Thanks so much

y[n] = { 2, -3, 4, -2, 1 }
⇧

thank you so much. my professor makes this as convoluted as possible in class

Sorry but this doesn't seem to work in all case. Try the following example, it fails: x[n] = d[n] + 2d[n-1] - d[n-3] , h[n] = 2d[n+1] + 2d[n-1]. If you do the tabular method you end up with y[n] = -d[n+4] - 2d[n+3] + 2d[n+1] + 3d[n+1] - d[n-1]. That answer is incorrect, the true answer would be y[n] = 2d[n+1] + 4d[n] + 2d[n-2] + 2d[n-1] - 2d[n-4]. If I found one example of where it doesn't work, there's bound to be infinitely more.

Thank you so much 💕

thank you sir

great video indeed !! but a little doubt that is as convolution is performed here, don't we need to flip one sequence ???? then do the rest of the thing

Never heard of such a straightforward method before, and WOOOW! 😍

Very good content really so helpfull

y(n) = (2,-3,4,-2,1)= 4 is the value where the 0 is place

This method is a lifesaver. Why don't they teach this in my uni

Y[n]={2, -3, 4, -2, 1} where 4 is element when n=0;

Thank you, and what is the procedure if one signal has 5 values and the other 4 values And dont have the information of n=0 (no arrow pointing)

😍😍😍😍😍♥️♥️♥️♥️

Y[n]=(1,2,4,6,8,8) then intersection of x1[n],x2[n] is 8 then which one is X(0) is please give me reply

y(n) = { 2, -3, 4*, -2, 1} ,,,,,,tnx sir

Hello Neso academy. Is there a reference (a book/article/paper etc) which i can cite in my report (i need citation) for the above tabular method. Thank you.

LoL

Is it necessary that no of rows should be equal to no of columns

Good

N value is taken as per our wish

Thank you so much sir, Im taking signals and systems 1 atm, wouldnt be able without ur videos, thank u again and love ur channel

really they done a very hard work......... thank u..

You have motivated me to practice and learn Digital Signal Processing, your job is very great and excellent thank you so much. Appreciate it from you. Keep up and please keep up the good work. 🙏🙏🙏😃😃😃 You really motivate me to always learn my lessons with you.

I really thanks to neso ,because such a good staff is teaching us❤️

what do u do when the number of values for X1 and X2 are different, u can just put 0 for the the less numbered signal but how do we know if it should be on the left or right?

Thank you brother my doubts is clear how to find origin for different situation .❤️❤️

Thanks a lot

y[n]= {2,-3,4,-2,1}
↑
Is it correct, Doctor?

Thank you Dr. so much 💕
Your explanation was great👌🏻

is this method only applicable only when we are given values of discrete system or we can also use this method for given equations of x[n] and h[n] ?

great work broo. i love u

Y[n]={2,-3,4*,-2,1)

A lot simpler method than Graphical Represent method.
Thanks sir.

Excelente aula!!!!!

Its a matrix method not tabular..

I never forgot your help my dear brother god always bless you 🤗🤗🤗🤗

this help me a lot. thanks

I thought this was matrix method

This was on the FE exam for electrical engineers...

y【n】 = { 2,-3,4,-2,1}