Nested Lists | Python | HackerRank

l1=[]
l2=[]
for i in range(int(input("Enter how many students: "))):
name=input("Enter your names: ")
marks=float(input("Enter numbers: "))
l1.append([name,marks])
l2.append(marks)
l2=list(sorted(set(l2)))
lo=l2[1]
l3=[]
for i in l1:
if lo==i[1]:
l3.append(i[0])
l3.sort()
for i in l3:
print(i)


my programme

Thank you Excellent teaching.

Instead of using another FOR LOOP in the end to just sort the names, we can use,

for val in sorted(res):
if m==val[1]
print(val[0])

mark = float(input())
EOFError: EOF when reading a line.
I am getting like this sir plz give me solution

recently started learning to code, this was a way better explanation compared to other sources. thanks /\

finished watching

You have made coding so easy.Thankyou so much

thx a lot

Thank you sir

nice explanation sir.....

Really nice explanation

the explanation is clear, awesome

very well explained

i really like the way of your explanation .... you explanation is mind blowing........😇😇😇

You are a great teacher! What a nice explanation!

Great job there. Although I used a different method, your video helped me to link the least with the student name:
(it got only 7/10 but I'm happy that my own idea worked little. I'll use your idea to improve mine :) )
if _name_ == '__main__':

n = int(input("Enter number of students: "))
data = [] # list of name and score
jscore = [] # list of just the score


for i in range(1, n+1):
name = str(input(f"Enter name of student {i}: "))
score = float(input(f"Enter the score of student {i}: "))
lis = [name, score] # to temporarily store each student data entry
data.append(lis) # added to data list


for student in data:
jscore.append(student[1]) # just the list of scores

least1 = min(jscore) # first least score

while least1 in jscore:
# to remove first least score even if it's present multiple times
jscore.remove(least1)

least2 = jscore[0] # second least score

names = [] # to store names of students who have second least score
for student in data:
if least2 == student[1]: # matching second least score to students in data list
names.append(student[0])

for person in (sorted(names)): # sorting alphabetically and printing each name in new line
print(person)

loved the way of explanation

carry on 😌

❤🙏

Hi
can someone explain the code from line number 16.
I'm not clear with the val is being accessed with the indexing in the nested loop. To access element in nested loop won't it be. How will the for loop iterate with val in res?
to access the first val in res. won't we write to access the first element inside the inner list:like val[0, 0]

why am I getting this IndexError: list index out of range

Very well explained 🙌🏻❤️

Great explanation

Thank you man!

good explained. Thank you

nice bro thanks for clarity🥰

Wow!!! how perfectly you explained each line of the code ,you explained all the logic behind each line so perfectly. Thankyou so much for the explanation. 😇

Excellent teaching bro. Really I see so many but I can't understand .. once saw your video clear cut explanation.....do like this way of teaching

Wow amazing and simple concept . thanku for your great explanation

excellent explanation sir but ..while submitting code test case 3,4,6,9 are getting failed

bhai kya bath hai yaar you're amazing

Very neatly explained. Thank you

high quality content. thank you so much

Thank you so much sir . The way you explain really cool . 😇🙂

thanks sir its really goad explanation for every one to understood code easily. and its very helpfull for me . u are great

thank you very much bro

excellent. but this code do not run if there are multiple high grades.

Nice explanation I searched everywhere but all were shortcuts, thanks a lot

Thank you so much for this easy explanation!

Thank you
It was very easy to follow.

thanks bro 👍🏻

Thank you

Thanks for such a wonderful explanation. I very much happy after seeing such a video. Thanks

Tqs bro for explaining in a clear manner 👏👏

thank you brother.... its really helpful to understand

I am getting error . will u please help?


n=int(input())
res=[]
grade=[]
for i in range(n):
name=input()
score = float(input())
res.append([name,score])
grade.append([score])
grade=sorted(set(grade))
m=grade[1]
name=[]
for val in res:
if val[1]==m:
name.append(val[0])
name.sort
for i in name:
print(i)


Error:
grade=sorted(set(grade))
TypeError: unhashable type: 'list

Thank you so much..really really well explained

good explaination