strcpy() and strncpy() functions | C Programming Tutorial

nice, thanks

Hii its me again :P
I have a situation where i have to copy the end of the string instead of the first few characters of the string, how can I do it?
Eg. you input into the terminal going './bin/library bin/books.txt' but i just need the 'bin/books.txt' bit to be used inside a fopen() function, and the .txt file could be another file name with longer characters, so how can I make it possible? Thank you!

Nice - thank you Kevin.

What compiler do you use like in general the app you use

strlcpy()? strcpy_s()?

Thankyou so much

thank you so much. please I have a question how we can use all that using the pointers ?

thanks kevin well explained 🙂

Thank you so much. You are a life saver, man.

Why the code below doesn't produce any error? I use 9 as the size of the destination string even though I have to specify 10 or more (because of the \0 character)

char src[] = "12346789";
char dest1[9];
printf("%s",strcpy(dest1,src));

Good video, but it doesn't contain enough information to rebuild strncpy(); yourself.

We have to put 10 characters in src[10 ] because we count from 0 so we can put our 10 characters and \0 will put at 10 (11)

Hello. I've been using DevC++ and a terminal (in CodeChum), and then when I tried:

char src[10] = "123456789";
char dest2[5];
strcpy (dest2, src);

printf ("%s", dest2);
return 0;

They are still printing the exact 123456789. How could have this happened? Help please.

Mr.Portfolio Courses. I have 12345678, how a can copy only 3456 ????

Perfect! Thank you very much!

Hi! What’s the editor?