For Loop In Python | 10 Problems Solved & Explained | Python for Beginners

Sir, Please 🙏 reply
I am a first year student
Mere collage me sb c aur c ++ sikh rhe hai including me . par ai aur machine learning jisme me interester hu usne python ka role jyada hai hai to me c aur c ++ sikhu ya python par shift kru ?

Thankyou so much bhai

More easy way to solve Qno.9:-

n = int(input("Enter a number: "))
for i in range(2, n+1):
if n ℅ 2 == 0:
print("Number is not prime!")
break
else:
print("Number is prime!")

While

Thank you so much 🤩

Much needed series , we want more videos ❤

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Please code this by using space 😒

While ❤❤❤

while

Really needed bro❤

Thank you, please post more of these videos.

Great series bhaiya plz continue this amazing series ❤

yes sir it helps us can you make more video on list tuple and function

needed series but bhai i'm practicing for data analyst so can you please give us some that type of videos using python.

while

Thanks a lot.

bro plz while loop bhi thanks a lot 😍😍😍

More easy way to solve Qno.3-
for i in range(2,11,2):
print(i , end = " ")

Sagar Bhai reply do kya ham Mobile se python sikh sakte hai kya 😢

We want more such videos like this🙌

while

Question 7 can also be solved as:
a , b = 0 , 1
total = 0
for _ in range(10):
print( total , end = " ")
a ,b = b , a + b
total = a

Bhai jan web development kab start kr rahy django ke sath

Sagar bhai abi jo newz ai hai kay 25% code Ai say ganreate keya ja raha hai abi python learn krni chaheye nahi

Thank you bhai ❤

que. 5 much simpler way
word = 'python'
for i in word[::-1]:
print(i, end= "")

Thank you sir

Q6.
str=input("Enter string: ")
lst=[]
for i in str.lower():
if i=='a' or i=='e' or i=='i' or i=='o' or i=='u':
lst.append(i)
print(len(lst))

Q6.Method 2
str=input("Enter string: ")
lst=[]
word='aeiou'
for i in str.lower():
if i in word:
lst.append(i)
print(len(lst))

Yeah bro we need more videos like this

Thank you bhaiya ❤❤❤❤❤❤

Ye needed thi aur chaiye.....

Easy way to solve the question no. 10 is :
a ='programming'
for letter in a :
S = a.count(letter)
print(f ' the no. of the letter {letter} is : {S}')

Thank you bhaia .Keya ap python ke orbhi questions Kara sakte he . using oops, function

Was Needed..and more Required

Thank you bhaiya much needed for ip class 11

function and dictionary ke Problems solve video bana le na.. pl

word ="python"
a = len(word)
for i in reversed(range(a)):
print(word[i])
Too easy❤

Thanks 🙏

Continue this playlist. It's very useful ❤
Watching from Bangladesh

After writing the code that your wrote for Q6, it was not giving the proper output.
vowels = ["a", "e", "i", "o", "u"] # Correctly list individual vowels
word = str(input("Enter a word: "))
count = 0
for char in word:
if char.lower() in vowels: # Ensure comparison is case-insensitive
count += 1
print(f"Total vowels in {word} is {count}")

Had to make two changes. Am I the only one facing the problem?

Sagar bhai aap bata do plz
i=1
small=?
while i<=5:
a=int(input("enter a no"))
if a<small:
small=a
i=i+1
print("smallest no is",small)

? Iss me kya hona chahiye bata o
Bhai abb hi bata do 😢

Sir please make a full course while and for loop besic to high😢

Sagar sir please give lacture of how to solve the pattern by using for loop

❤❤❤❤❤

Nice broo 👍

bhaiya is tarikee se bhi ho sakta hee


n = int(input("Enter no. :"))
if n <= 0:
print("positive no.")
else:
for i in range(1, n + 1):
if (n - 1) % i == 0:
print("not prime")
else:
print("primer")

Thank you sir ji