Комментарии:
You explained it so nicely sir
ОтветитьEven i tried once. But not succeed. That's now got done. Really great work. Thank you so much.
ОтветитьGood explanation 👍
ОтветитьThank you verymuch 👍
ОтветитьHi basant thanks as usual nice explanations
ОтветитьGreat video.. Thanks for the effort 👍👍
ОтветитьHow to do decryption in production without eclipse
ОтветитьThankyou🙏
ОтветитьWhat is benefit ...secure properties file from whom ?.
ОтветитьWe implemented in our project
ОтветитьWhy we need to encrypt passwords this way if we can simply set passwords as Environment Variables in server or Jenkins?
ОтветитьHow can I add notification to recruiter when someone apply for a job offer added by this recruiter with Spring boot and angular?
ОтветитьThanks sir,
In configuration class we exposed encryptor private key password. ie javatechie .can anyone decrypt by private key
Thanks man. best channel ever.. All the best !!
Ответитьthank you so much!!!
Ответитьvery informative video. Can you please guide how to implement the default behaviour using a bean ?
ОтветитьHello Sir , below command is use for Maven but For gradle can you please provide the command"mvn jasypt:encrypt-value -Djasypt.encryptor.password=javatechie -Djasypt.plugin.value=Password"
ОтветитьFailed to bind properties under 'spring.datasource.password' to java.lang.String:
Reason: Failed to bind properties under 'spring.datasource.password' to java.lang.String
Can you help me please?
Can you please show this demo with build.gradle?
ОтветитьWhat would be the gradle equivalent command for this?
ОтветитьYou are simply the best
ОтветитьThanks! I got it working!
Ответитьvery informative and clearly explained,your channel always gives real-time knowledge
Ответитьhi, how can i run the jar file? after this?
ОтветитьWhat about when you use two values for password. For e.g : ENC() , ENC ()
Ответитьvery helpful, thank for making this video
ОтветитьExcellent tutorial!
Ответитьmvn jasypt:encrypt-value -Djasypt.encryptor.password=javatechie -Djasypt.plugin.value=Password
Oddly, this command runs successfully from Windows command line, but not in IntelliJ terminal:
[ERROR] Unknown lifecycle phase ".encryptor.password=javatechie".
Can I use my own Encryption algorithm ?
ОтветитьHi. Thank you very much for this helpful presentation. I just have a question. I'm trying to run the following code below for my 'dev' profile but it is not working although it builds successfully. It only works in the default profile. Do you know how to resolve this? Thanks in advance.
mvn jasypt:encrypt -Djasypt.encryptor.password=JaveTechie -Dspring.profiles.active=dev
how to encypt using java code command line is clear.
Ответитьthis is 128 or 256?
Ответитьmvn is not a recognized as internal or external command. How to fix this?
Ответитьsir,
jasypt-spring-boot-starter vs jasypt-maven-plugin
whats the diff?
how to get vn configuration option in eclips
Ответитьvery well explained
Ответитьhow can I maven install after encryptin? It says "Description:
Failed to bind properties under 'spring.datasource.password' to java.lang.String:
Reason: java.lang.IllegalStateException: either 'jasypt.encryptor.password', one of ['jasypt.encryptor.private-key-string', 'jasypt.encryptor.private-key-location'] for asymmetric encryption, or one of ['jasypt.encryptor.gcm-secret-key-string', 'jasypt.encryptor.gcm-secret-key-location', 'jasypt.encryptor.gcm-secret-key-password'] for AES/GCM encryption must be provided for Password-based or Asymmetric encryption
Action:
Update your application's configuration"
it is very clearly explained, thanks man
I have one question, in configuration file we are entering the Key directly isn't that cause security issue
your channel always gives real-time knowledge
ОтветитьHi. If we are deploying our application where do we have to store the key? Coz if someone knows the key he can easily decrypt the password. Right?
ОтветитьIf the encrypted values are once deployed on github, if someone else wants to clone the repository and try running it, how will he know the key? Where should key be stored?
ОтветитьHello bro please help me
ОтветитьVery well explained sir! How to do this encryption if we have multiple passwords to encrypt, if I define multiple vm arguments like -Djasypt.encryptor.password = xxxxx, -Djasypt.encryptor.password = yyyyy, it takes only the last value we provide
ОтветитьHi please Respond , our client asked to not use PBEwithMD5DES encryptor as its going to be decrypted. what other option do we have
ОтветитьWorked fine...Thank you.
ОтветитьThere is also Cipher class within the standard jdk, no need to have any dependencies.
Ответить