Frequently Asked Java Program 26: How To Count Occurrences of a Character in a String

Superb easy to understand sir...thanks a lot for helping us.

import java.util.Arrays;

class OccrenceOfInputArray {

public static void main(String[] args) {
int arr[] = {1, 1, 2, 2, 3, 4, 5, 6, 8, 9};
int len = arr.length;
System.out.println("Total length: " + len);

String arrString = Arrays.toString(arr);

// Replace '2' with an empty string and get the length
int totalCount = len - arrString.replace("2", "").length();
System.out.println("Total count of 2: " + totalCount);
}
}



sir, while im running this program after removing the 2 we got the output is 8, but here output is getting is: -18..........please clarify this doubt sir

not a good approach

import java.util.HashMap;
import java.util.Scanner;

public class Main {
public static void main(String[] args) {

System.out.print("\nEnter a statement: ");
Scanner scan = new Scanner(System.in);
String statement = scan.nextLine();
scan.close();

String[] words = statement.split("\\s+");
HashMap<String, Integer> wordHashMap = new HashMap<>();
HashMap<Character, Integer> letterHashMap = new HashMap<>();

for (int i = 0; i < statement.length(); i++){
char currentChar = statement.charAt(i);
if (letterHashMap.containsKey(currentChar)){
letterHashMap.put(currentChar, letterHashMap.get(currentChar) + 1);
} else {
letterHashMap.put(currentChar, 1);
}
}

for (Character letter : letterHashMap.keySet()){
int count = letterHashMap.get(letter);
System.out.println("Letter: " + letter + " appears " + count + " times.");
}

for (String word : words){

if (wordHashMap.containsKey(word)){
wordHashMap.put(word, wordHashMap.get(word) + 1);
} else {
wordHashMap.put(word, 1);
}

}

for (String item : wordHashMap.keySet()){
int count = wordHashMap.get(item);
System.out.println("Word: " + item + " appears: " + count + " times.");
}

}
}

I think string.chatAT(i) ==letter and count ++ will do the job right

Sir Your explanation is very nice and am very thankful to you sir

Sir we can use Hashmap that would be more efficient

I was very scary to make understand coding earlier. But once I started watching your videos, my thought process changed.
I am very comfortable to understand your logics, I feel like "OH CODING IS SUCH SIMPLE" 😄🤣
Great Thank you Pavan sir..🤝🤝🙏🙏

hi sir can we use this method is scanner sirif yes can u tell me how to use it

Amazing video sir ! You code in such simple way and explain it so well that any basic /intermediate base person can fully grasp the concept and learn coding.

Thank You Sir... You Make My Logic Building Strong... Simple And Up to The Mark Explanation...😇🙏

sir please make more interview programs

Sir make program video of duplicate characters in a string

why writing this much complex...i dont know............

we can write in this way too

String s="yash is a good boy ";
char comp='a';
int flag=0;
for(int i=0;i<s.length();i++){
if(s.charAt(i)==comp){
flag++;
}
}
System.out.println(flag);

This question asked me today

Sir what about when there are same letter with upper and lower case.

Not working giving output as zero

Excellent explanation

this is easiest program i have seen ..thanks sir

impressive.

if we get string from the user then how to get max occuring character

corrupted

This for known statement.. Then what is code for when we use scanner Class

Sir y u removing a es

What about no case sensitive

Great explain....🙌🙌

This is working but does not count uppercase characters if we are pass lowercase or vice versa

we simply sovle the problem like
int count =s.replaceAll("[^a]","").length();

very easy sir.thank u. sir can u please make programm for prime no. from array ..please sir .

Love your videos and commenting for better reach. You have a great voice btw.

Thankyou sir for this video...

This was asked in my interview

Tell for all character occurences. For all occurences it will become a very exhausting code

can u tell me how to check for all the character occurence

this method is also easy check it guys'
String str="java programming is very easy";
int count=0;


for(int i=0;i<str.length();i++) {
if(str.charAt(i)=='a') {
count++;
}
}


System.out.println("number of occurances letter a :"+count);
try this one also easy and thank u sir for these videos

Can i get this in loop.. if yes can u comment the statement..

Nice explanation however I am bit confused, as we count the spaces as well in index., So when we are replacing a with space, the space would still be counted. so not sure how did it work. Could you please explain the logic for that. Thank you

Thanks for easy explanation and can we do the same program without "replace" method? please explain the approach as well

Bonne vidéo

Nice explanation