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I had a problem where I needed to input the formula for finding the electric field at distance r from the center of two hollow sphere's containing a uniform charge of q-sub-1 and q-sub-2. Then, it asked what the charge was on the interior and exterior of the surface of the spheres.
ОтветитьThank you very much.
Ответитьsomeone can explain to me why the elecric field in the conductor is not just 0(it is one of the rules of conductors)?
ОтветитьIF I PASS MY MIDTERM, IT WILL BE BECAUSE OF YOU!!! THANK YOU
ОтветитьThank you very much!! Wonderful teaching.
ОтветитьPerfect video! What about r1=0 though? Do integrals come to play there?
ОтветитьI like the way you solve the exercise
Ответитьthe question a it says that there is a positive charge at the center!
Ответитьthank u so much
ОтветитьHow is e= 0 if there is a charge at the center? in the first example?
ОтветитьThankyou
Ответитьyou got a) wrong you said that there no charge at the center therefore E=0 but the question said +20 uC at the center
ОтветитьNope you got it wrong man
ОтветитьIn first example I understood that there is no electric flux if there is no charge inside the imaginary Gaussian surface. The cylinder is positively charged, which means that electic field is going outside of surface. So there should be electric field going towards hollow. But as per Gauss's law there is no electric. That is the confusing part. Why we have to take Gauss's law as granted ? Where is derivation?
Ответитьi love you
Ответитьi hate physics but you're videos make it tolerable. thanks!
ОтветитьI was completely lost scrolling through videos, and this is the one that saved me. Thank you very much!
Ответитьcannot thank u enough :')
ОтветитьI would recommend the tutor to show a real picture of the speher in the upper corner to ease the imagination in the followers head.
ОтветитьThanks for all the amazing help !! This is replacing my zoom class
Ответитьbless your soul
ОтветитьThis video saved my life
ОтветитьCharge should be outside ri8?
ОтветитьSorry but its wrong .The Gauss' law is WRONGLY stated .. its not the product EA but the closed integral of the dot product of E and dA(or simply net FLUX) that is = Qenclosed/e. Surprised to see so many people took it at face value .
And no , net charge inside a gaussian surface need not be zero for electric field to be zero . There could be electric field lines passing the gaussian surface but the net FLUX will be zero because net inward flux is gonna be equal to net outward flux ... Its simple physics.
you r great:)
ОтветитьI'm not gonna lie this was the first vid I've seen where I'm low-key confused. Nothing against your teaching, I just think this is a hard concept to begin with.
Ответитьin the second problem:
when we are calculating the field at r1 why don't we calculate the field of the positive charge of the conductor
but why E=0 inside there still electric feild
ОтветитьBt i think in this electric field outside the sphere will be zero
Ответитьi cant help but feel totally lost in the first 2 minutes. really wish you would redo this video for clarity.
Ответитьon the last part what if both charges are positive/negative
ОтветитьYou are a legend dude
ОтветитьAt second problem, is the spherical shell has 15 uc conductor or nonconductor? Could anyone give my any info about this?
ОтветитьNicely explained concept
ОтветитьTX sir
ОтветитьCorrection: I meant to write that the +20uC charge should rest on the surface of the hollow sphere as oppose to the center.
ОтветитьDo not follow this, this is wrong
ОтветитьI think the question was poorly worded
ОтветитьSir a conducting spherical she'll having charge q uniformly distributed on its surface and Q charge is at the centre of given sphere. What is electrostatic potential at R/2 from centre?
Ответитьsorry this is so so wrong
ОтветитьWHY is it sometimes we use 4PIr^2(area) and sometimes 4/3PIr^3(volume)?
ОтветитьThnq sir
Ответитьmy man!!! this video came in clutch! thanks
ОтветитьThanks iam very glad that we hv such a person to help we students when we get stucked up
Ответитьthanks bro
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