DC Series circuits explained - The basics working principle

Answer : Yes . Led will light normally because circuit current is 1.9A.

0.0195< than 0.02 A

the current will be 0.019 amps

Hi Paul! Could you make a video on -48VDC that is used in datacenters?

Question about resistor in series: when you have a high value resistor and a lowe value resistor, does it mstter which resistor is "first" ? Im thinking if you yave the lower value resistor first, couldnt that burn up ? If not, why?

i could be wrong but i believe you made a mistake to the final question answer on your website. you used the first method but forgot to do voltage squared so you listed 9v / 460 ohms and got the answer of 0.0195A. but if you do 81v/ 460 ohms the answer is 0.176A. am i confused or did you make a mistake. sorry just trying to understand

why the logic board of mac mini m2 pro does not have these kind of resistors. what kind of resistors is there?

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IR

0.0195 Amps

net resistance=460
voltage=9v
current=v/r
=9/460 (AMPERE)
0.019Ampere

Just one wat h of this before starting a DC cor units class gives you a significant chance at a higher grade kids.

Interesting thing just happened. I tried to test out the equation with my breadboard, and using a 9v batter and 10 ohm resistor burnt out my resistor. Anyone have any advice on what I did wrong?

I have a bunch of broken electronic toys that I would like to fix.

This is the best!! I used today at work when I had to convert 2V signal to 4 mA signal because the sensor was taking mA and our controller was able to send only 2-10VDC signal and I wasn’t sure how to connect the resistor. Then I watched the video at work, understood everything and everything worked after I placed the 500 Ohms resistor in series. Thank you very much!

0.19565A

Great video! Quick question - why is current represented using A? I thought current was represented using I?

0.18A sir.

19.56 mA

why can't we use a resistors instead of fuses

How come for the last formal you have voltage squared but don’t in your answer? Leads me to a different conclusion

Thank you so much for all of this.

I went into my school lesson not even knowing what a circuit was

Who else is here for self betterment through information 🤔💭💭🧐👨🏾‍🎓💰💰

Late to a lesson as always! 😅 So, his answer to the quiz is confusing me. W=V2/ohms which should be 81/460=0.176 which is more than 0.02. can someone help explain this? His answer: 9V ÷ 460 Ohm = 0.0195A

watchin this for a&p school, ur a godsend for actually explaining WHY things happen and not just "thats how it works"

This is interesting but I zone out when the math is involved lol

Thank you for this video "DC Series circuits explained" 👍

I’m on Christmas break for college and I’m here watching videos to have knowledge for next semester. I can’t believe I’m saying this but I am a nerd 😂.

Sorry if this is a confusing or dumb. When he talks about watts in the end of the video, is he talking about it being the power consumption of the all the resistors? Or if he were to put a light bulb on to the circuit, That the bulb would be powered with how ever many watts with a 9V battery at the end of the of the circuit.

i have a question, why do the volts stay the same throughout the entire circuit even when the resistors are affecting the flow, if you measure before the first restrictor ( by using a multi meter first wire ) to the end of the last resistor ( last wire ) , its somehow still 9v. i know that the resistor restricts energy flow but if individually it can be seen that the flow is lesser while the flow is normal altogether from both resistors. how does that differ from just measuring together rather than individually?

i thought maybe it speeds back up when left unrestricted but measuring (via multi meter) from before first resistor and after last resistor will give you 9v still even though according to my idea its basically imitating a long individual resistor.

im confused in my head Dx

thanks a lot sir...great explanation

I like the questions at the end they're fun and engageing.

Thanks Paul. I have subscribed and liked as well.

It will 19mA

Can anybody help please? Does it matter where you are going to place resistor? I mean would it make difference if I place resistor after the buld or before the buld, so it doesn't burn out?

I was thinking that you have to place resistors close to negative end of battery where the electrons flowing from, and before the bulb, but in the video I can see that resistors are placed after the build relative to the current of electrons...
Please, help to clarify)

YES,the current less than 0.002A coz the total current was 0.019A.Or approximately 0.002A and the LED LIGHT comes On.

Currently in Army BET lab, and this stuff went over my head today. Probably would have helped if it wasn't a class done completely by computer with minimal instructor guidance, but that's a complaint for the AAR.

Thank you so much for making these videos- I might actually graduate this course.

Fantastic.....

Amazing video well done, by the way, yes the current will be less than 0.02A

Question. If AC is changing poles with respect to its frequency. Then why tester doesnt glow on both wires ( phase and neutral) ??

My Dad is cool

0.019