Q. 2.4: Reduce following Boolean expressions to the indicated number of literals (a)A'C' + ABC + AC'

Well explained sir pls upload more vedio on digital logic💕💕

Pls upload 2-17 and 2-18

just solving question not explaining

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Tq sir

ABC+A'B'C+ABC+A'BC'+A'B'C' kindly Sir Solve this Expression to 5 literlas

Mataculas lecture

final equation we get is (AC+A'C') we should count A and A' as seperate literals or same???

in b part I m getting 2 literals xy

sir please expalin X = A+AB’C+A’B’+AC’BD’

Sir, in (D) question why you took 2nd and 3rd terms to obtain common.. We can take 3rd and 4th terms na sir? (Time duration:6:15) and what is the answer for A'A'sir?

Thank you sir 🙂

sir! in question (b), how can u write? from{(x.y).z'+z}=(x+y+z).z'+z??

thank you so much Sir

thank you for your explanation!

very nice ....
Fast and cool approach to solution

Thank you sir

how to solve this..B(CD+C'D')+AB'(C'D+CD')

Thank you sir

A'B'C'+A'BC'+AB'C'=C'(A'+B')
plzz ans batao sir isaka koi bhi batao plzz....

Helpful ❤️

Sir having one doubt in these two following questions:
Could you please check whether their answers is correct or wrong.
Q. Obtain the complement of the following Boolean expression:
1) f= xy'+x'z
Ans: y.x+x'z'+y.z'
2) f= x(y'z'+yz)
Ans: x' + y.z' + z.y'
Sir could you please tell

4th sum I'm not understanding sir plz once again explain

shzada

Simplify by Boolean algebra:     AB'C + A'B' + ABC'D

You are amazing sir.

THANK YOU SO MUCH

sir plzzzzzz tell me how to download this book??? plz

Love from Bangladesh sir..this is really helpful.thank you sir for making this playlist

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Thank you so much sir ❤️

Can You tell me the book from where these questions are from

thank you doc dhiman

sir plz explain (x'.y')'=(x+y) how