Комментарии:
Superb sir
ОтветитьPlz upload fourier trasforms
ОтветитьThx a lot sir for all these videos, I have exam of Signal on 12/12/2017, u have already covered 1.5/4th of my syllabus,. Also I studied whole of ur digital elx playlist as well, plz try to upload next videos as soon as possible so i can cover more and more of my syllabus from ur videos thx again
Ответитьthe solution just blew my mind. thank you. this is amazing.
Ответитьyou have a Good experience! THANKS
ОтветитьSuperb
Ответитьhello sir your explanation is very good.. but i have a doubt why you not take limits from 0 to T for convinence
ОтветитьThank u sooo much for all these lectures
Ответитьwow just wow
ОтветитьThanks a lot sir for all these lectures
ОтветитьWhy u choose x(t)=&(t).
x(t) should be &(t-nT). Plzz guide me 🙏🤔
While doing integration u had said that integration of dell of t from -t/2 to +t/2 is is t actually at t=0 only the value of integration exists then how can we consider the area sir
ОтветитьThank u sir
ОтветитьSIR WHY DO WE CONSIDER THE PERIOD AS -T/2 TO T/2 AND NOT 0 TO T
Ответитьhow do you choose Cn or C-n in the previous example we worked with Cn where we had -jnwt
Ответитьgood explanation........Thanks
ОтветитьWhy u wrote e^jnwot as formula is e^-jnwot
ОтветитьYour explanation was so clear as always, Thank you
ОтветитьIf we choose the limits 0 to To , then what will the value ???
ОтветитьI was confused too so^just a reminder here, when computing x(t) we have summation Cn.e^(jnwt) but when computing Cn we have integral 1/T x(t).e^(-jnwt)dt
ОтветитьAwesome explanation
ОтветитьThank you very much. You are a genius. 👍👍👌👌🙏🙏🔝🔝
ОтветитьHow the area of impulse came out to be 1... how a single line can give area other than 0??
Ответитьwhy we are using sampling property in this specific question??
Ответитьthere is no point of doing the solution as answer is in 1st step, filter from options
Ответитьvery clear and simplistic explanation
ОтветитьHow did we get to know that it is complex Fourier series and not trigonometric Fourier series?
Ответить