Комментарии:
Bhai fone silent kar liyo
Ответитьthanks :)
ОтветитьThank you ❤
Ответитьur too fast in ur explanation and some time not clear in words sir.
ОтветитьYou calculated total no of pages=(size of VA/ sizeof page size). In this, I think u calculated size of VA in the wrong way. 32 bit system will ensure 2^32 different entries and each entry will be of 32 bits, so size of VA should be :
total entries*size of one entry(32bits)=2^32* 4=2^34
Rest of the calculation seems ok.
So final answer should be 8MB:
Total no of entries in page table =2^34/2^12=2^22
Total no of frames=2^26/2^12=2^14
size of one entry in page table=14/8~2 bytes
So total size of page table=2*2^22=2^23 = 8 MB
Thank you so much sir, you have no idea how much we needed this explanation
Ответить2^26 how you write
Ответитьthank you so much
Ответить*BODY SODA WAS HERE*!!!!!!!!!!!!!!!!!!!!
Ответитьu saved my life
ОтветитьSir, please take a class clearly. Because this is sum. Sir, I can't understand this
ОтветитьThank you sir this full concept make me able to solve the question thank you so much sir..
ОтветитьThank you so much, it helped me alot to understand the basic concepts ❤️. Can you tell me from where i can gell all the necessary formulas for solving paging questions 🙏🙏 or from where i can solve more paging related questions
ОтветитьThis helped me thank you!
ОтветитьWow, good job😃👍
Ответить