Propositional Logic − Logical Equivalences

love your videos man, really helpful, thank you veru much!!!

Amazing way of teaching...

DawDology !

What's more important than proving this thing is you gave a proper explanation of what a logical equivalent are🤦‍♂️ In my University the professor was just like read it this are formulas🤣

If only the test is this easy

Thanks

I have a test today and this confirmed I will be failing that exam.

Ivanni nerchukoni....evadivi peekali raaa...bongulo maths....chaduvuthunte chiraaaku benguthundhi....🥲😤deenemma errihooku subject ...🔥

“Right”

This is the hardest part of logic

for absorption law (a), another way to think is that either p or p and q needs to be true for the expression to be true. Hence if p is false, the expression has to be false and if p is true the expression has to be true. So its equivalent to p. Similar logic holds for (b)

Thanks for your best tutorials!!🤩

is there any sites where we can practice these questions

Your teaching is so nice or understanding thank

Would be nice if you put the correct answer to your question in description so i can confirm if my answer is correct or not.

can you just add some english sub?

I'm watching this for 7th time .. but still can't 💔

Awesome explanation!

Girl I don't Carpe Diem.
I Carpe Dior.

please provide the notes for all lectures🥲🥲

Thank you Indian Guy(i dunno what's your race is) but it really help me a lot since I have midterm exam today

Made me realize how simple it is.

thank you very much dude, I am just learning this for myself as I have graduated from school long time ago. but bruh! wat in the multiverse is this shoot! Aliens laugh at us with all these nonsensical convention we brought. I am learning and laughing at this!

please teach me!

Excellent !! Excellent!! nothing else to say.

You please do some video lectures ( even paid ) on model checking buchi automata etc.,

Negation(p implies q) equivalence p and negation of q
Using (p implies q) equivalence to negation of p or q
Negation ( negation of p or q) equivalence p and negation of q
Then use de Morgan rule
P and negation of q is equivalence to p and negation of q

sound quality is very bad

can somebody help me with conditional question #8

5th no solution:
¬(p->q)≡p^¬q...

Prove:
RHS=p^¬q
=¬(¬q->¬p) (as p^q=¬(q->¬p)
=¬(p->q) (as p->q=¬q->¬p)
=LHS

Thank you sir all of my doubts finally got cleared

ATTENDANCE: BSIT-6A
REPLY TO THIS COMMENT FOR CONFIRMATION.

شكرا و جزاك الله خيرا

Thanks

HELPFUL VDO

5. Question. Not(p->q) <=> p ^ Not q
Soln.
Not(Not p v Not q) <=> p ^ Not q
p ^ Not q <=> p ^ Not q

Tommorro is my CCE and I am here for the first time today😄

now this is the kind of stuff which is complicated and simple at the same time due to this channel !!!!!

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Really helpful and yes I have done my home work ☺️😁
Thank you sir 😊

great video!

Awesome man

Thank you so much ❣❣💯💯❣❣
I am from Algeria and I enjoy to see your vedios🥰🥰🥰

discrete math makes me want to die

What is happening

Can I ask if a distributive can be two statements only, something like
(p v q) ^ ¬p ≡ ¬((p v q) →p)?