Intermediate Algebra Lecture 13.1: A Study of Conic Sections -- Parabola and Circle.

Something that might help in comprehending the vertical and horizontal shifts is understanding that each polynomial could individually be equal to zero. In finding the X component of the center of a circle (x-2)^2 + y^2 = 2^2, if the (x-2) = 0 then X = 2, and then turn around an do the same for Y.

For me this is an easier way to think about it. Its the exact same thought process as finding X and Y intercepts for linear equations, just being applied to a different type of problem.

Do you teach at any particular college?

Solid!

Professor Leonard sent me from his calc 3 chapter 11.6 video to here!

what about these sir,

(x - h)² = 4p (y - k)

(y - h)² = 4p (x - h)

how are these related to the formulas you have just taught to us??

Who's here for Cal III?

It's hard not to turn math into a spectator sport with Prof Leonard teaching.

Professor, looking at the equation of a circle I wondered if humans invented the equation to fit a pre-conceived idea, or if the equation of a circle already existed just waiting to be discovered.

Wait your test are multiple choice? I wish I would of had you as my professor you saved my life while taken statistics (which I took online) and now with algebra. Thanks a lot Prof. Leonard.

Thank you so much for these wonderful videos.

awesome Prof

good job professor

thaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaank u soooooooooooooooh much

thank you so much prof , l just don't get the vetex how to find it ?

what about y=4ax^2 how does that differ from this ?

Thanks!

I found out your channel short time a go and it is totally amazing. Thank you a million 😍😍😍