How to Solve Coefficient of Friction Down a Ramp

TYYY!!!!

Thank you! This was very helpful!

thank u soo much this was really helpful ;)

are there any question without the mass?
just the degree and the force?

You just saved me so much thanks legend

What if we don't have acceleration

Wow I never understood this and u made it so clear 🔥✔️ Thank you

What if you don't know the mass? How would you find it with the information provided?

thank you very much

You're a legend my friend.

So does the angle affect the coefficient of kinetic friction?

Thank you this helped me alot :)

THANK YOU SO MUCH!! spent hours trying to figure this out and you made it so simple!!!

how would i solve this if i had a hanging mass?

THANK YOU !!! I can finally finish my lab assessment 💀💀💀

Finally I can sleep peacefully tonight. Thanksss

Thank you

very good explained and easy to understand

what d0 y0u d0 if y0u d0nt have accelerati0n?

Is this for class 11

What happens of I don't know the acceleration down the ramp?

THANK YOU VERY MUCH MAN REALLY APPRECIATE IT! Gruß aus deutschland!!!!!!

I just want to thank you for making this video. I was trying to find the process for solving this problem, and you broke it down and explained it so well that I had no trouble following. Your work is making lives better! God bless you and I wish you joy, peace, good health, and all the best :)

Hi! Is there any way to solve for μk without kinetic force and with an acceleration of 0? Or is it just the same process with 0 taking the place of 3 (in this problem)?

how do you solve without mass but you have time and distance.

is mgsin(theta) and mgcos(theta) correspond with parallel or perpendicular components? Or do they differ depending on the problem? I'm having trouble understanding because my professor taught us parallel and perpendicular components and then solve with trigonometry.

2020:p

Thank you so much I did this in in term 1 of my year 11 and have completely forgotten how to do it and because exams are soon i needa revise and you have saved the day, cheers

solved this in 2 steps using f=ma , i know that the resultant force is 10x9.81sin40 minus friction and friction =nxr (mew times reaction force) so r= 10x9.81cos40 so using f=ma 10x9.81sin40 minus n(10x9.81cos40)=10x3 and just solve for n!! (for those who are confused feel free to message me on instagram @scott_and_charlie_fishing!) same as what he did but just shorter!

Totally helpfull for me too tonight :), thanks for this vid

I know you made this a while ago, but I just wanted to say thank you for making this video! It was very helpful, clear and easy to follow. Anyway, keep it up and I look forward to any new and helpful physics content. Stay safe, stay happy and healthy :)

10.0 X 9.8 X sin(40) = 73.0, not 63... ?

how did he get 33 N for Fk

Well explained