IBM Coding Questions 2023 | IBM coding Questions for ASE role | IBM Programming Question 2023 | IBM

THE FOLLOWING HOLDS TRUE ONLY IF THE ARRAY STARTS 1
def find_missing_element(arr):
n = len(arr) + 1 # Since one element is missing
expected_sum = n * (n + 1) // 2 # Sum of first n natural numbers

actual_sum = sum(arr) # Sum of elements in the array

missing_element = expected_sum - actual_sum
return missing_element

# Example usage:
input_array = [1, 4, 3, 6, 2]
missing_element = find_missing_element(input_array)
print(f"The missing element is: {missing_element}")

int main()
{
int n; cin>>n;
vector<int> v;
for(int i = 0 ; i < n ; i++){
int x ; cin>>x;
v.push_back(x);
}
sort(v.begin(),v.end());
for(int i = 0 ; i < v.size(); i++){
if(i+1 != v[i]) {
cout<<"missing"<<i+1;
}
}
return 0;
simple logic broo......

Sort(arr.begin, arr.end+n);
For(int I=0;I<n;I++){
If(arr[i]!=I)
return I;

arr = [1, 2, 3, 5]
def ans(arr):
n=len(arr)
ans = [0] * n
for i in arr:
if 1 <= i <= n:
ans[i - 1] = 1
for i in range(len(arr)):
if ans[i] == 0:
return i + 1
return -1
print(ans(arr))

Please Bring Logic Building Doubt Solving Series On Java Programming Soon.

import java.util.Scanner;

public class Main{
public static void main (String[] args) {
Scanner scan = new Scanner(System.in);
int n = scan.nextInt();
int arr[] = new int[n];
for(int i=0;i<n;i++){
arr[i]=scan.nextInt();
}
int demo[]=new int[n+1];
for(int i=0;i<n;i++){
demo[arr[i]-1]=1;
}
for(int i=0;i<demo.length;i++){
if(demo[i]==0){
System.out.println(i+1);
}
}
}
}

Hello sir. I have registered for Hero Campus Challenge (Season 8). Can you please suggest me some tips to win this challenge?

Did anyone receive link today

I passed 2 case out of 7 , what is chances to clear exam

You has a one mistake on your code bro ...
ans = [0]*(len(arr)+1)
Other wise your got index error ..

Bro I have Exam Today IBM Coding Exam
Pls help me bro