Комментарии:
Thankyou, well explained
ОтветитьThank you very much!
ОтветитьThanks Sir🙏🙏
ОтветитьWhy does 2nd condition exists only in left half of the s plane ?
Ответитьthe therom is applicable for which type of inputs.please anyone answer this question
Ответить😍😍
ОтветитьTQ u so much sir ....well understand
ОтветитьIn initial value thm, you are representing intergral 0- to inf as 0- to 0+ and 0+ to inf whereas in final value theorem not like that. What is the reason behind this. Pls tell me.
ОтветитьYou are exceptional
listned to soo many of ur lectures
What are poles and zeros please explain.
ОтветитьSuper explaining sirrr
ОтветитьFinal value theorem is also not applicable for conjugate roots of S.F(s) ..am i correct ...plz clarify my doubt
ОтветитьThank you so much sir
ОтветитьThank u so much sir
Ответитьvery good lecture but there is one mistake in that.The domain of t is >0 for the applicable of initial value theorem as it is one of the conditions for laplace transforms. lim t->0+ f(t)
Ответитьmush have all poles or must have poles on left side of s plane ?
ОтветитьThank u sir
Very easy to understand
And u are providing good quality education
sir pls make note on quantum mechanics...
ОтветитьSir please cover Z-Transform and Inverse Z-Transform
Ответитьkindly update z transform quickly
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