#21 Python Tutorial for Beginners | For Loop in Python

Thanks

for i in range(1, 501, 1):
j=i*i
if j<=500:
print(j)

a = []
i=1
while i<=500:
a.append(i)
i+=1
for j in a:
if j*j<=484:
print(j*j)

let us know the nested for loop

task solution:

import math as m
i = ()
for i in range(0,501):
if (i == int(m.sqrt(i)) * int(m.sqrt(i))):
print(i)

I hope it is right

Sir you teach awesome but its my humble request to add more questions of every topic to make our concepts crystal clear

quiz to print perfect square:
for i in range(1,500):
print(i**2)

for i in range(1,500):
print("square number of" ,i, "is",i*i)

for i in range (1,501):
for x in range(1,25):
if i == (x*x):
print(i)

Perfect squares numbers between 1-500


import math as m
for i in range(1, 500, 1):
j = i/m.sqrt(i);
if i % j == 0:
print(i)

Answer-1
for i in range(1,501):
if (i*i)<=501:
print(i*i)

excellent explanation

import math
for a in range(500):
b = math.sqrt(a)
if math.ceil(b) == math.floor(b):
print(a)
idk if this is the most efficient but its the only thing i could think of

for i in range(1,501):
if (i*i<=500):
print(i*i)

for a in range(1,501):
if a==0:
pass
else:
print(a*a)

for i in range(1,500):
if m.pow(i,2) < 500:
print(m.pow(i,2))

don't forget to import math

from math import sqrt
for i in range(1,500):
if sqrt(i)%1==0:
print(i)
alternative way

for i in range(500):
if i**2<=500:
print(i**2)

For loop

Program not run

Hello

i=1
res=0
while res<=500:
res=i*i
print(res)
i+=1

for i in range(1,100):
if i*i>500:
break
print(i*i)

Hey Navin thank you for this wonderful video !!!!!! 😊
Be bit slow please 😅 concepts are well clear but you are doing so fast 😂

Want give suggestions tht most of guyz are not able to understand ur language as u speak very fast. No doubt ur teaching style is gud bt atleast u can speak slowly.

Thank you so much Navin! I totally appreciate the pace and thoroughness of your videos. I'll be watching!

answer to the quiz is:
from math import sqrt
for i in range(1,500,1):
for a in range(1,500,1):
if(sqrt(i)==int(a)):
print(i)

for i in range(23):
print(i*i)

import math as m
for i in range(1,501):
if m.floor(m.sqrt(i))-m.sqrt(i)==0:
print(i,end=" ")

Thanks Telusko 🌠

your explanation is very good sir, i have suggest your playlists to my other friends whose are learning websites.

Thank you Sir 🙏

for i in range(1,23):
print(i*i)

can you explain do while loop

Answer is - for i in range(1,50,2):
print(i)

# output is
1
3
5
7
9
11
13
15
17
19
21
23
25
27
29
31
33
35
37
39
41
43
45
47
49

for i in range(1,500):
if i<=22:
print(i**2)
else:
break

learning from you sir

Solution for E1
# print all the perfect square number between 1 and 500
for i in range(1,501):
if i**0.5 == int(i**0.5):
print(i, "is a perfect square")

For loops here way better than java

Best explanation of for loop. Will never get confused. Thankyou so much

thanks for the video

Bro you are a life saver

Thanks a lot your videos really so useful!

Loving this series

Good explanation

answer:
for i in range(1, 501):
if i ** 0.5 % 1 == 0:
print(i)

Import math
I=1
for I in range (0, 501) :
if math. sqrt(I) = = int(math.sqrt(I) :
print (I)

Hi, plz tell me how to write 3 statements in for loop and assign a new value
And if cindition which will run after loop completion in the same prog

I wonder if I can use this for a list of lists. If I have some data I want to write to a CSV, maybe I could use a for loop that references each list and writes it as a line in the CSV