Math Olympiad Challenge (x+2)(x+3)(x+4)=990 | Best Trick...

Your way it’s very difficult u can do it easier

We know that X+2, X+3, and X+4 are 3 consecutive numbers.

990 = 9x10x11

therefore, X+2=9, X+3=10 and X+4=11
So, X=7.

THAT SIMPLE

Gay

999 = 999
990 = 990
?
at 9.24
the check checks that
999 ≠ 990 ?

9 x 10 x 11 = 990. So x = 7 works nicely. Factor 990 and the answer becomes apparent.

Letra ruim .

I wish people would also put in the complex solutions for these equations which are always far more interesting.

X also equals -8 +/- sqrt 74 i

easy

(x+2) (x+3)(x+4) to iloczyn trzech kolejnych liczb który równa się 990.
Rozkładam na czynniki liczbę 990 i patrzę czy są trzy kolejne czynniki których iloczyn równa się 990. Są takie czynniki : 9,10,11. Stąd x =7.

10 x 10 x 10 is 1000, so the x is likely a little under 10. So wouldn't you simply start with x a little below ten and try out some integer solutions?

Ans: 7