Can you solve 3 Thieves crossing River Puzzle || 3 Thieves and Coins Bags

Thanks for this brain twister 😂

1) Either 'B' or 'C' should ride with his bag.
2) The one who rode before has to return.
3) 'A' should ride with other's bag.
4) 'A' has to return.
5) Both 'B' & 'C' should ride together.
6) Either 'B' or 'C' should return with his bag.
7) 'A' should travel with his bag.
8) Person other than 'A' has to ride with his bag.
9) Both B & C should ride together.
10) 'A' should ride alone.
11) 'A' should travel with other's bag.
12) Person whose bag is on the other side has to ride.
13) The one who rode before has to return.

Is there anyone who can solve this in coding

In the real world, Thief A would just shoot B and C in the face; combine all the coins into one bag and jump into the boat.

C is looking cute actually 🙂

Please solve the puzzle below
A farmer has coconut trees and he packs the coconuts in a sack and take it to market to sell them. Each sack can carry maximum of 50 coconuts. On the way to the market there were 50 tollgate and he has to pay 1 coconut as toll fee for every sack.
1. If he carries 100 coconuts how much he will have when he reaches market?
2. If he wants to have 100 coconuts after reaching the market then how many he has to carry from his home?

If you had posted any similar puzzle let me know the link
Thank you.

I wasn't thinking that you could cross with someone else's coins

The first thief crosses the river and says "See you around, bye-bye!"

And by the time they manage to solve the riddle, the cops were already cuffing them

Question wasn't clear. And thief A didn't run away

Beautiful solution

they need a rope to pull the canoe back

how that two thieves not stealing away the money on the other side if the puzzle is done by you and rules are only applicable for me

Isn’t C chilling with the thousand dollar bag?

This is the question asked in my Interview and probably he watched this video I guess!!

your solution is wrong because it is against the 1st rule, if one stays wtih 2 bags can leave, so not accepted

Either C or B can go first with their loot. Then follow same procedure for same result.

Maa kasam kilwayenge ki leke nhi baangna 😂😂😂

There is a simple solution. Take thief A and his coins over, leave gold, and return with thief A. Take thief B over with his gold. leave gold and return with thief B. Take both thief A and B and leave them with their gold. Take thief C and his gold over.

It can be solved more easily in other process!

When Thief A crosses with a bag of 300 coins, what's to stop him from simply walking off with both bags, and leaving the other two on the other side? When Thieves B & C were together on the other side, what was to stop them from simply walking off with their respective bags? The same question applies for Thieves A & B when they were together. This solution doesn't take the rules given at the start into consideration. You have three separate times when a thief could simply walk off with his money or more money than he started out with.

The problem is not clear at all.

I guess Some logic is missing with distribution of of coins in the 3 bags

3 mins 42 seconds

👎

Took me some time but I solved it... Good puzzle

when he can carry 1000 coins then the man can carry 700 +300 coins when he returns empty (the man who has 1000 coins)

And the Irony is police came and sent all of them to jail

And the fact is A went away with 1000 coins

I would just call the cops

First first each other than who wins take all three bags

solved it using 6 pennies and a marker. too hard to solve on paper.

Its their personal matter we should not disturb them..😂😂😂

Okay, so I'll take the goat first, then the cabbage, come back with the goat, trade the goat for a wolf and drop the wolf with the cabbage and then go get the goat

Get some big boat,fuel cost is too high😅😅

I got the half way then i lost track

I did this a different way and started with A. It seems like a working solution but I guess I must have gone wrong somewhere.

It's a nice solution, but logically speaking there's a flaw in it based on two given facts:
- If they will steal from each other, they are likely to screw each other over in different ways as well.
- The thief who takes the boat first has no incentive to help the others once he is across with his gold.
...
So what actually happens in this scenario is that the 3 thieves plan out the clever solution stated at the end of this video to make sure they all keep their own gold. Thief B takes his gold across first as per the plan, then thief B waves goodbye to them and leaves. Thief A and Thief C are stranded on the wrong side of the river with no boat, and the police catch up to them. They swear revenge on Thief B and tell the police who he is. Thief B goes to prison too, and nobody keeps any gold.
...
There also seems to be a plot hole concerning a thief left alone on the wrong side of the river with a bag of gold larger than his own. If he can simply run away with the new larger bag of gold, then none of the thieves actually need to cross the river. The most logical solution then is for none of them or only one of them to use the boat. The one who gets to use the boat is probably the Thief A with 1000 gold, since he must be the leader of this band of thieves or he wouldn't have gotten 50% of the loot. The next most likely might be Thief C with only 300 gold, since he might just be a hired getaway driver and not know the others well. Only Thief B, who is not the leader but clearly better treated than Thief C by the leader, is unlikely to be the one to go his own way. So the entire scenario goes against premise -- we are missing a key detail. Why do the thieves want to cross the river? Does it improve their chance to escape capture? Without a motive, we can't understand the full nature of the problem. Details matter.

At point, A and 1000 same time...so he will chace to escape...??