Solving Exponential Equation

Thank You, Professor 🙌🙌🙏🙏

Thank you very much professor 👍

If you wanted to include imaginary solutions, you could write -3 in its polar form (3e^ipi) and then take the natural log of that to get another solution, ln3+ipi

Nice vídeo.

Thank you so much❤

Thank you so much❤

Brilliant !!

Nice one, can you make a video about the gauss-jordan elimination

You explain complicated problems so simply. Easy to understand!

.e^x-12e^-x-1=0
Dikalikan dg e^x menjadi
.e^2x-e^x-12=0 yg berarti
.e^x=4 & e^x=-3
.x=log4/loge=ln4

Wow .. thank you sir

=(e^x-4)(e^x+3)=0=>e^x={4,}=>x=log4

i wish you the best wnbk w5yrt kbire 💘💘

Awesome, you make it look so simple. Thank you!

By multiplying the equation by e^x for both sides
e^2x-e^x-12=0
Let e^x=y
y^2-y-12=0
(y-4)(y+3)=0
y=4
y=-3
e^x=y=4
Take ln for both sides
xln(e)=ln(4)
x~1.4
y=-3=e^x
Rejected

Exelent

Solving the quadratic independently, I completed the square and obtained the same result for X, discarding the negative alternative for X

Excellent! Congratulations on the clarity of your explanations!

You made it look so simple. Thank you.

Please make a video to find angle of inverse ratios(sine, cosine....)

Man I really kind of miss studying algebra and calculus after watching your videos for a few days. Your skills are top notch. 👌 👍

I watched this 2 weeks ago. Still dont understand it fulky, but its like this cloud of uknowing slowly is become more and more clear to see through.

What an excellent instructor, clear and showing all the steps and excellent shortcuts. Where were you when I was in college (40 years ago)?

And e to the x will never be 0. If it were 0=0 , and any x is a solution... an infinite 1. But then the equation does not need be exponential.

math

ex-12e-x-1=0

ex-12e-x-1 = 14 1 12x3=36+3=39 1.39 0 -1 ex 13x3=39 1.39-1.39=0

0=0

Great vid, many thanks, Sir!😊

Outstanding. Succinct

e^x-1-12e^-x=0
(√e^x-4√e^-x)(√e^x+3√e^-x)
√e^x=4√e^-x dan √e^x=-3√e^-x
e^x=16e^-x dan e^x=9e^-x
e^x=16/e^x dan e^x=9/e^x
e^2x=16 dan e^2x=9
e^x=4 dan e^x=3

Is someone able to build a solution in Excel/Google? I'm having a hard time solving for a complex exponent in Google/Excel. This is based on a financial formula.

A=P*((1+r/n)^(n*t))+x

Solving this for (t)

(A-x)/P =(1+r/n)^(n*t)

At this point, I think I need to use a log function to get the exponent out, but if I capture (t) in "log(1+r/n,n*t)", I'm really not sure what to do to get (t) out of the function.

Please help!

Excellent lesson. 👍

Put directly epoer x euals a .. now its very quick solving

I wish I had YOU as a professor!

e^x -1/12e^x -1=0<=>
e^0 -12e^-0 -1=-12 <=>
e^1 -12e^1 -1=-2,69<=>
e^1,385 - 12e^-1385 -1=0,009<=>
x=1,385

e square power 2=e power 9

Thank you professor for you sharing your knowledge 👍🏻

Nice problem.

On the last step, you can reexpress ln(4) as 2ln(2) and since ln(2) ~= 0.693 is more familiar to a student and more likely memorized than ln(4), we would not need a calculator.

nice explanation ❤