Комментарии:
Hello very cool project
ОтветитьNice sir
Ответитьwhich sensor is used in the anemometer ?
Ответитьhi, where can the anemometer be purchased, how can we get the code.
Ответитьwhere can i find the codes?
ОтветитьCool sir. But what type of anemometer that you're using sir?
Ответитьhelp me arduino code send please
ОтветитьIs it possible to store the data in a flash drive as .csv instead of printing them on the screen?
Ответитьnice project, very god explantion, have u Published this on github? thanks
ОтветитьBrilliant tutorial! Thank for your time! I have the same anemometer but I use it with an ESP 8266 and ESP Easy firmware. The raw value is 136 which I can convert via the Two-Point Calibration. Which I have done. 136 = 0.000 m/s and 680 = 32.4 m/s I have placed the anemometer right next to my other weather station t match the values. It is pretty accurate, but it could be better. My other station is publishing data every 15 sec, the question is it raw data or the weather station use s some sort of smoothing or averaging calculation. So anyway I just try to find out if my calculations are right? What are your calculations? I have tried to find the answer from the video but I am not sure. :D Thanks.
Ответитьhi can you do this example with a raspberry pi board please
ОтветитьMetric units rock! So do you. Thank you for this video. 👍
ОтветитьAm I wrong or arduino (atmega) doesnt support true double type variable?
Ответитьplease can I have the code, scratch
Ответитьi'm getting a constant output voltage of 5V.... Even when the anemometer is not rotating. Can you please help?
Ответитьwhich sensor is used in the anemometer ?
ОтветитьNice project all the best👍
ОтветитьI couldn't find the code anywhere, copied it from the video. Works great! Thank you!
ОтветитьThe +9v rail from the battery to the Ardiono does not look right
ОтветитьSir.......
Could you plz send me the code
where can i get the code? thanks
ОтветитьHow did you get the number of voltageConversionConstant = 0.4882814?
ОтветитьBrilliant, exactly, what I need. Thank you for sharing !
Ответить