Комментарии:
Very cool. Thank you for sharing
ОтветитьThx Bro!
Ответитьamazing shot! Cool bro :)
Ответитьthanks... 😊
ОтветитьCool Bro...
ОтветитьTKs brow. clean and easy!
Ответитьawesome tutorial for me, thank you! please keep them coming.
Ответитьhow to retrive dropdown list in view
ОтветитьRất hay, cám ơn bạn. Nếu có thể bạn demo thêm các functions khác như create, edit, delete nữa thì hay biết mấy.
ОтветитьI get an error that the
List < MVC_5_with_Entity_Framework.Models.ForumReply>
is a type, which is not valid in a current context :(
How do I create an object for one of the models on the particular view?
Ответитьgg dude
ОтветитьThank you. I did it, but can you tell me is there any other way to solve this?
I'm little confused with this: List<blabla.Models.Genre> genre = Model.ToList()[0] as List<blabla.Models.Genre>;
Good one...although I was looking for the logic...I was captured by the music... music is too inspiring :)
Ответитьthanks
ОтветитьThis is aweful. Use a ViewModel instead!
ОтветитьHello Sir,
Thank you for such a good video.
but when i try same
@model IEnumerable<object>
@{
List<OIMTRY01.Models.Message> MessageList = Model.ToList()[0] as List<OIMTRY01.Models.Message>;
List<OIMTRY01.Models.Comment> CommentList = Model.ToList()[1] as List <OIMTRY01.Models.Comment>;
}
its gives null at MessageList and CommentList
Anyone any answer??
Thanks!!! It's real helpful to cross join table!!
ОтветитьThanks. It is helpful and easy!
ОтветитьThank you, great Job bro
Ответитьit worked thanks bruh xD
Ответитьwhat a waste. and turn down that fuckin music!!!
Ответитьlol, I love how he clicked on his song before doing the tutorial xD
ОтветитьI have exception That tell me " system.ArgumentOutOfRangeException. The index was out of bonds. It must not be smaller than the size of the collection. Someone help ?
Ответитьworks wonderfully! thank you
Ответить