Problems on Ages - Shortcuts & Tricks for Placement Tests, Job Interviews & Exams

8) m1+m2+m3+m4/4=19
m1+m2+m3+m4=76 (total age of all members is 76 yrs)
4 yrs back , 4members *4=16 yrs
Total age =92 yrs ..
After the birth of child
m1+m2+m3+m4+m5/5=19
m1+m2+m3+m4+m5=95
92+m5=95
m5=3 yrs

For qn 3)
Let ages of Rohan , Ajay , Meena be R , A , M ..
Rohan is younger to Ajay so their difference of ages A-R
Rohan is elder to Meena so their difference of ages R-M
A-R=R-M
A+M-2R=0
Gn: A+M =108
Sub ,
108-2R=0
R=54 yrs

Excellent 👌

In the final question how the average became 19.?..

But sir....in question 7 ) let assume scenario of cricket : if player plays 4 match and in 1 match he scored 0 run , in this scenario we don't remove that one match and calculate average dividing by 3, instead we divide total runs by total matches...inow come to this ...if one of friend is just born i.e. he is 0 year and some minutes or days old...means he exists...so why we dont divide 120 by 4 instead 3 ? 🤔🤔🤔😅😅😅

Now i understand i have no common sense

Problem 3 is not understanding me

Cool teacher❤

Your voice is so good😂

your way of teach topic of ages are bit complicated

The present ages of Aman and Nina are 59 and 37 years, respectively. What was the ratio of the ages of Nina and Aman 13 years ago?

Just fantastic 😊

In question no. 4 if the meena's age is 83 it doesnt satisfy the sentence that " the sum of the three ages of rohan meena ajay is 132" could you please justify your answer?

good explaination sir.. i like your teaching and explanation method ... thanxs a lot sir, you are giving good knowledge to us🙏🙏❣❣

I had learned all the reasoning part from your channel and now I don't think find it difficult anymore. Thank-you so much Sir 🙏🙏🙏

I don't understand 🙄am I dumb

I don't have common sense sir😔

Suchh a nicee explanation...very interesting...

Thank you ❤️

Thanks a lot for the amazing explanation

7. Total age of 4=(4*36)=144 yrs.. Without the youngest friend total age =(144-6) =138 yrs..this is the total of 3 friends.. Now avg of 3=(138/3)=46 yrs.. So at the time of birth the avg age was 46-6=40 yrs

Thank you

Sid sixt questions can be solved very easylu by considering S7 and S3 and substituting in s18+T=165

Q8)avg age of 4 family members=(A+B+C+D)/4=19 A+B+C+D=76 eq1
present age if family members and a new child=(A+B+C+D+E+16)/5=19 eq2
sub 1st eqn in second easy answer

Helpfull🤗

Could you please make the video on coding inequality sir..

kindly make a video on set theory

Thanks for providing such variety in your questions.

Everything is easy, you just need to learn the basics and keep practicing.

Did not understand your explaination

Can we refer this questions for icet exam

Thank You Sir, I understood well the concept of problems based on Ages...!

For Q.2
I think answer is wrong because p,q is considered as present age.
The answer might be p,q age is 24,16 respectively.
present age of p=3x
Present age of q=2x
3(2x-12)=(3x-12)
6x-36=3x-12
X=8
Therefore p age==3*x=3*8=24

❤️❤️❤️

Nice explanation

Q8 why are we even solving this question ,in statement they are clearly saying 4 yrs ago baby was born so definitely his age right now is 3 years .

in q#7 avg o group has to be taken six year back , even though youngest ager was 0 we have to consider him in calculating average. ie [0+(A-6) +(B-6) +(C-0)] /4

Very long trick tym west plz shor ttrick vdo uploaded

From where can i get the questions to practice?

Sir where is Ur tricks
U just solving through theory.
We need to solve questions within 15 to 20 seconds

Sir, in Q-3. If suppose asking about Meena's and Ajay's age, how will you find?

👍

Question 2 Answer will be come 84, please cheak

These methods are time consuming methods... Plz tell us shortcut techniques

Thanks sir..

In question no7 we need to consider the youngest also 6yrs ago he was born which means he is there so we need to count him as the 4 th member avg = sum /total no of members i.e avg=120/4= 30

Thank u sir

Sir why did you deal about averages concept in ages concept... Please change it sir...