Комментарии:
Original method .
First square on both sides ... Since right hand side function is repeated infinite times we can write it same as y
Therefore y² = sinx + y
y² - y = sinx
Now differentiate ...
( 2y - 1)dy/dx = cos x
dy/dx = cosx /(2y-1)
Rap😂
ОтветитьWhat a trick 😅
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ОтветитьKartik-arre Dinesh sir
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Easy hai sinx ko chhorhke sare ko "y" lelo fir both side squaring both side karke differentiation kardo khatam
Ответитьand how to integrate that type of function?
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ОтветитьQuestion wrong 2nd function's root is only over the sin x.
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ОтветитьSecond order derivative dile kya hoga
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Ответитьlogarithmic differentiation laganeka original method
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Performance
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Sir ha Que ala hota ajj 14may 2nd shift fkt -sin hote me tych -cos barobr kele
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Ответитьdy/dx = cosx/2y-1
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