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|(a, b)=2, |(a b c)|=3, |(a b c d)|=4, ...., |(1 2 3 ... n)|=n because a cycle of length n has order n.
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Ответить讲的形象生动易懂
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ОтветитьI think we should call a two-cycle a bi-cycle.
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Ответитьjust tell me how many permutaions of all 118, known elements
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ОтветитьCould we perhaps express this as some sort of polinomial?
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ОтветитьYou explain in 12 minutes what my professor tries to explain in 90 mins and 50 slides and we still don't get it...
Ответитьn-cycle has order n.
ОтветитьSo order is the same as th number of distinct elements in cycle
For e.g:
(1 2) has order 2
(1 3 5 ) has order 3
(1 7 8 9 ) has order 4
And so on
Am I right?
Super clear explanation, Thank you!
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ОтветитьAlso confusing, should a.b be written first as 2 and then 1? 1>3>2 ; then 2>2>1 >>>( 2,1) (though equal to (1,2)) , similarly b.a: 1>3>1 >>(); 2>1>3; 3>2>2 >>>(3,2) ==(2,3)
ОтветитьGreat Tutorial! But there are things that went too fast toward s the end on multiplication. Can you please reply on this? "We are back to where we started giving us a cycle (2,3)"??
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